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The searchlight effect in hyperbolic materials

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Abstract

The quasistatic field around a circular hole in a two-dimensional hyperbolic medium is studied. As the loss parameter goes to zero, it is found that the electric field diverges along four lines each tangent to the hole. In this limit, the power dissipated by the field in the vicinity of these lines, per unit length of the line, goes to zero but extends further and further out so that the net power dissipated remains finite. Additionally the interaction between polarizable dipoles in a hyperbolic medium is studied. It is shown that a dipole with small polarizability can dramatically influence the dipole moment of a distant polarizable dipole, if it is appropriately placed. We call this the searchlight effect, as the enhancement depends on the orientation of the line joining the polarizable dipoles and can be varied by changing the frequency. For some particular polarizabilities the enhancement can actually increase the further the polarizable dipoles are apart.

© 2013 Optical Society of America

1. Introduction

Interest in hyperbolic materials, in which the dielectric tensor is real but with its eigenvalues taking different signs, has surged following the discovery of superlensing. The story of super-lenses itself had its genesis in three pivotal papers.

The first by Veselago [1] suggested that a slab of dielectric constant ε = −1 and magnetic permeability μ = −1 could act as a lens. This is indicated by ray tracing, taking into account the negative refractive index of the slab.

The second by Nicorovici, McPhedran, and Milton [2] (see also [3]) showed that in two-dimensional quasistatics one could have apparent point singularities appear in the field surrounding a coated cylinder with coating having dielectric constant ε = −1 + , in the limit δ → 0. Specifically, with rs and rc denoting the shell and core radii, and with a dipole source at x = z0 outside the coated cylinder located in the annulus a2/rs > z0 > rs where a=rs2/rc it was proved in that paper that the complex potential V(z) outside the coated cylinder, where z = x + iy converged as δ → 0 to the potential

V˜e(z)=1zz0(1εc1+εc)a2z02(za2/z0),
for all z > a2/z0, where εc is the dielectric constant of the core. [The physical potential is Re{[V(z) +V()]eiωt/2} where ω is the frequency and t is the time.] Thus an apparent point singularity appears at the point z = a2/z0 which lies outside the coated cylinder. In the limit δ → 0, the shell acts to magnify the core by a factor of rs/rc so it has the same response as a cylinder of radius a and dielectric constant εc (becoming invisible if εc = 1) but now the ”image dipole” lies in the matrix. Within the radius a2/z0 > |z| > rs it was numerically found that the potential develops enormous oscillations. This blowing up of the field within a localized region dependent on the position of the source, now called localized anomalous resonance, may be physically regarded as a localized surface plasmon and is responsible for a type of invisibility cloaking [4, 5], that has been the subject of considerable study [615].

The third pivotal paper by Pendry [16], which served as a catalyst for the field, made the bold claim that the Veselago lens would be a superlens, capable of focussing much finer than the wavelength of the radiation. The appearance of apparent point singularities caused by localized anomalous resonance was later found to justify this claim for fixed amplitude point sources [3, 1727] though a single polarizable dipole is cloaked rather than perfectly imaged when it is sufficiently close to the superlens [4, 14, 28], and a small dielectric inclusion is at least partially cloaked [6, 9, 29]. Despite all the work on this topic (the paper of Pendry has over 6,700 citations) it remains an open question as to whether large dielectric inclusions (which interact with the surface plasmons) are perfectly imaged when they are close to a superlens: work by Bruno and Lintner [6], would indicate they are not perfectly imaged (in the limit in which the loss in the lens goes zero) while work of [29] suggests that they may be perfectly imaged, though it is not clear if sufficiently small loss has been taken in this latter investigation.

It was suggested by Pendry and Ramakrishna [30] that a stack of layers of equal thicknesses alternating between ε = +1 and ε = −1, would have an effective dielectric constant of infinity perpendicular to the layers and zero parallel to the layers, thus channelling the field like a set of infinitely conducting wires in an insulating matrix with ε = 0. If the two constituent materials have different thicknesses and/or the dielectric constants with unequal magnitudes but opposite signs then the effective dielectric tensor can be a hyperbolic material (one needs to add a small loss to the material with negative dielectric constant to justify this, both physically and mathematically) and the dispersion relation in such materials allows for real wavevectors with arbitrarily large wavenumbers, thus allowing for propagation of waves with arbitrarily small wavelength [31]. The breakthrough came with the independent recognition of Jacob, Alekseyev and Narimanov [32] and Salandrino and Engheta [33] that a multicoated cylinder or sphere with many thin coatings with dielectric constants of alternating signs would correspond to a hyperbolic material with radial symmetry and be capable of magnifying an image from the subwavelength scale to a scale where conventional imaging would work: the hyperlens was born. This was subsequently verified experimentally [34, 35].

In this paper, our interest is in the two-dimensional quasistatic dielectric equation

εV=0,ε=[εx00εy].
In the hyperbolic medium we consider εx is real and εy = εx/c2 with c = − + η where η is a small positive parameter (μ and η are real constants). In this medium, as η goes to zero, (1.2) formally approaches the wave equation,
2Vy2=μ22Vx2,
and thus in this limit one should expect wavelike solutions in the hyperbolic medium (think of y as the time and μ as the wave velocity). In this paper we study how field singularities arise in the limit η → 0 when there is a circular hole in a hyperbolic material, and we study how a pair of polarizable point dipoles interact in a hyperbolic medium when a uniform field is applied at infinity.

It is known that both temporal and spatial dispersion play important parts in the design of hyperbolic metamaterials in the near visible spectral regions [36]. However, the incorporation of temporal and spatial dispersion into our analysis would lead to significant complications, and might obscure the interesting physical effects we discuss on an in-principle basis. We stress also that our derivations do not assume properties of materials appropriate to any specific spectral region, and are thus quite general.

2. The field around a circular hole in an anisotropic lossless medium

Here we review the known solution for the field surrounding a circular hole in a two-dimensional anisotropic medium, when the dielectric constants of the medium are real and positive. This problem has been treated before by Yang and Chou [37] in the context of the equivalent problem of antiplane elasticity, but their solution is more general than we need and they gave the potential only as an integral. In the next section we will use analytic continuation to obtain the solution when the dielectric constants of the medium are complex. For this it is important to express the solution in cartesian coordinates rather than in stretched elliptical coordinates (which would be dependent on the dielectric constants of the medium and become unphysical when the dielectric constants of the medium become complex).

Consider the transformation

z+r2z=2w,
which maps the circle |z| = r in the z plane onto the slit −rwr on the real w axis, and maps a larger circle |z| = r0, with r0 > r to an ellipse E, which in the w = u + iv plane intersects the axes at
u=±(r0+r2/r0)/2,v=±(r0r2/r0)/2.
The transformation (2.4) can be inverted to express z and 1/z in terms of w:
z=w+w2r2,1z=ww2r2r2.
It is to be emphasized that the square root needs to be taken so that the branch cut is a straight line between w = r and w = −r: for computational purposes one can set
w2r2=(w+r)(wr)/(w+r),
where the square root on the right hand side is defined with the branch cut along the negative real axis. Let us suppose the material outside E is isotropic with real positive dielectric constant εx, and now let us make some observations. First consider the potential γw which at the surface z = r0e equals
γ(z+r2/z)/2=γ(r0eiθ+r2eiθ/r0)/2,
and has complex conjugate
γ¯2(r02r0eiθ+r2r0eiθr02)=γ¯t,
where γ̄ is the complex conjugate of γ and
t=12(r02z+r2zr02)=w2(r2r02+r02r2)+w2r22(r2r02r02r2).
Thus the potential Re(γwγ̄t) vanishes on the boundary ∂E, while the potential Re(γw + γ̄t) has no flux of displacement field across ∂E (because the conjugate potential Im(γw +γ̄t) vanishes on ∂E).

Let us take a parameter c which to begin with we assume is real with 1 > c > 0 and let us make the additional stretching transformation

x=u,y=v/c,
which transforms the ellipse which intersects the u and v axes at the points (2.5) to an ellipse which intersects the x and y axes at the points
x=±(r0+r2/r0)/2,y=±(r0r2/r0)/(2c).
This final transformed ellipse will be the unit circle x2 + y2 = 1 if we choose
r0=1+c,r=1c2,
so that
(r0+r2/r0)=2,(r0r2/r0)=2c.
Inside this unit circle we put an isotropic medium with unit dielectric constant ε0 = 1.

After this stretching transformation the dielectric tensor in the exterior medium becomes

ε=[εx00εy],
where
εy=εx/c2.
The potential Re(γwγ̄t), expressed as a function of x and y will still vanish on the unit circle, while the potential Re(γw + γ̄t) will still have no associated flux of displacement field across this boundary (assuming the dielectric tensor of the exterior medium is transformed to the anisotropic value (2.15)) This trick of making an affine coordinate transformation to convert an isotropic matrix to an anistropic one has been used to find the solution for an isotropic sphere in an anisotropic medium [38] and to find the effective dielectric tensor of assemblages of stretched confocal coated ellipsoid assemblages (Section 8.4 of [39]). More generally it can be used to obtain explicit solutions for the fields around three-dimensional ellipsoidal inclusions in a uniform applied field with an anisotropic core and anisotropic matrix, each with arbitrary orientation.

Now consider a potential V(x,y) given by

V(x,y)=Re(βw+γ¯t)forx2+y21,=δxx+δyyforx2+y2<1,
where w = u + iv = x + icy and from (2.10) and (2.13) t is given by
t=(1+c2)(x+icy)1c2+2c(x+icy)2+c21c21.
At the boundary of the unit circle Re(γ̄t) = Re(γw) so continuity of the potential V(x,y) requires
Re[(β+γ)w]=δxx+δyy.
Also continuity of the normal component of the displacement field requires
nxεxxRe(βw+γ¯t)+nyεyyRe(βw+γ¯t)=nxδx+nyδy,
where n=(nx,ny)=(x/x2+y2,y/x2+y2) is the unit outward normal to the boundary of the unit disk. Since the potential Re(γw+γ̄t) has no associated flux of displacement field across this boundary we have
nxεxxRe(γ¯t)+nyεyyRe(γ¯t)=nxεxxRe(γw)+nyεyyRe(γw),
so the flux continuity condition (2.20) reduces to
nxεxxRe[(βγ)w]+nyεyyRe[(βγ)w]=nxδx+nyδy.
When β and γ are real, β = β′ and γ = γ′, corresponding to an applied field acting in the x-direction, then δy = 0 and (2.19) and (2.22) are satisfied when
β+γ=δx,εx(βγ)=δx.
These have the solution
δx=2γεxεx1,β=γ(εx+1)εx1,
and from (2.17) and (2.13) the potential outside the inclusion,
V(x,y)=βx+γRe(t),
equates to
V(x,y)=γ(εx+1)xεx1+γ(1+c2)x1c2+γc[(x+icy)2+c21+(xicy)2+c21]c21,
while the field inside is
V(x,y)=δxx=2γεxxεx1.

On the other hand when β and γ are imaginary, β = iβ″ and γ = iγ″, corresponding to an applied field acting in the y-direction, then δx = 0 and (2.19) and (2.22) are satisfied when

c(β+γ)=δy,εyc(βγ)=δy.
These have the solution
δy=2cγεy1εy,β=γ(εy+1)εy1,
and from (2.17) and (2.13) the potential outside the inclusion,
V(x,y)=βcy+γIm(t),
equates to
V(x,y)=γ(εy+1)cy1εy+γ(1+c2)cy1c2+γc[(x+icy)2+c21(xicy)2+c21]i(c21),
while the field inside is
V(x,y)=δyy=2cγεyy1εy.

3. The field singularities around a circular hole in a hyperbolic medium

The potential V(x,y) given by (2.26) and (2.27), or by (2.31) and (2.32), solves the dielectric equations when c and εx take any real positive value. By analytic continuation these formulae also solve the dielectric equations when c and εx are complex, and in this case V (x, y) is given by substituting the complex values of c, εx and εy = εx/c2 in these formula. The branch cuts in the square roots need to be taken so (for fixed non-zero η) there are no singularities in the field outside the cylinder. Guided by (2.7) we choose

(x+icy)2+c21=(x+icy+1c2)x+icy1c2x+icy+1c2,
(xicy)2+c21=(xicy+1c2)xicy1c2xicy+1c2,
where the square roots on the right hand side of these expressions have their branch cuts along the negative real axis. The expression beneath the square root in (3.33) will be real when
x+icy1c2x+icy+1c2=x+ic¯y1c2¯xic¯y+1c2¯,
(where the bar denotes complex conjugation) which is satisfied when (x,y) lies on the line
yRe[c¯1c2]=xIm[1c2].
Along this line the ratio in (3.35) will be negative along the interval between the points where x+icy=±1c2, i.e. between the points
(x,y)=±(Re[c¯1c2]Re[c],Im[1c2]Re[c]),
which will lie in the unit disk x2 + y2 < 1 if and only if
(Re[c])2(Re[c¯1c2])2(Im[1c2])2>0.
Numerically we have checked that the left hand side is always non-negative and zero only when c is purely imaginary. This shows that there are no branch cuts in the potential outside the circular hole when η > 0.

The parameters γ′, γ″, β′, β″, δx, δy, r and r0 are also generally complex. Let us take εx to be real and positive and c = − + η where η is a small positive parameter. Then

εy=εx/(iμ+η)2εx/μ2+2iεxη/μ3
is close to being real and negative. Since
(x+icy)2+c21=(x+μy+iηy+1c2)(x+μy+iηy1c2),(xicy)2+c21=(xμyiηy+1c2)(xμyiηy1c2),
we see that the potential V(x,y) given by (2.26) or (2.31) develops singularities as η → 0 along the four characteristic lines
x+μy+1+μ2=0,x+μy1+μ2=0,xμy+1+μ2=0,xμy1+μ2=0,
which are tangent to the unit disk touching it at the four points
(x,y)=(±1/1+μ2,±μ/1+μ2).
Figure 1 shows a plot of the absolute value of the potential V(x,y) showing how kinks develop along the characteristic lines

 figure: Fig. 1

Fig. 1 Plot of the absolute value of the potential V(x,y) around the disk given by (2.26) with an applied field directed along the x-axis and with parameters γ′ = 1, εx = 3 and c = 0.01 − i. The potential has kinks at the four characteristic lines given by (3.41) which are also drawn. Near these lines the electric field is huge.

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To better understand the behavior of the fields near these singularities let us consider the potential V(x,y) given by (2.26) in a region near the characteristic line x+μy+1+μ2=0 but away from the disk and away from the three other characteristic lines. In this region V(x,y) takes the form

V(x,y)=H(x,y)+G(x,y)x+μy+iηy+r,
where
r=1c21+μ2+iμη1+μ2,H(x,y)=γ(εx+1)xεx1+γ(1+c2)x1c2+γc(xicy)2r2c21,G(x,y)=γcx+icyrc21.
Near the characteristic line the electric field blows up as η → 0 and
VyμG0x+μy+iηy+rμG0h+iηs,
where
G0=γiμ21+μ21+μ2=γμ2(1+μ2)3/4
is the limit as η → 0 of G(x,y) on the line x+μy+1+μ2=0, and where
h=x+μy+1+μ2,s=y+μ1+μ2.
(Thus h measures the distance from the characteristic line x+μy+1+μ2=0.) So the local time averaged power dissipated in this region per unit area is proportional to
Im(εy)|Vy|2|G0|2μ2Im(εy)|h+iηs|2ηεx|G0|2μh2+η2s2,
in which (3.39) has been used to estimate Im(εy). Let us change variables from (x, y) to (h, s), so that dxdy = dhds. Observe that the right side of (3.47) is an even function of h and that the integral
0h0dhh2+η2s2=ln(h0+h2+η2s2)ln(η|s|),
when η is very small, and h0 is not too large (so the approximation of being near the characteristic line is still valid) has a dominant contribution of −ln(η|s|). So when η is very small we have
Im(εy)|Vy|2dh4εx|G0|2ηln(η|s|).
Hence along the characteristic line the power absorption (integrated across the line), per unit length of the characteristic line, goes as η ln(η|s|) which goes to zero as η → 0. However it extends a long way out along these characteristic lines so the total contribution does not tend to zero. To see this first note that the approximation (3.45) will clearly break down at large values of s, specifically when ηs is of the order of one, since then the right hand side of (3.45) becomes comparable to ∂H/∂y. Thus a ball park estimate of the total absorption coming from this characteristic line is
201/η4εx|G0|2ηln(η|s|)ds=8εx|G0|2.
The interesting point is that this total absorption remains finite and non-zero as η → 0. This explains the discovery of Sihvola [40] that a hole in a hyperbolic medium may have loss even though the medium is essentially lossless.

4. The dipole approximation for the far field around a circular hole in a hyperbolic medium

Consider the potential V(x,y) given by equation (2.26) corresponding to an applied field in the x-direction. When x + icy and xicy are both large we can use the approximations

(x+icy)2+c21x+icy+c212(x+icy),(xicy)2+c21xicy+c212(xicy),
to obtain
V(x,y)γ(εx+1)xεx1+γ(1+c2)x1c22γcx1c2+γc2(x+icy)+γc2(xicy)γx(εx+1εx1+1c1+c)+γcxx2+c2y2γ(εx+1εx1+1c1+c)(xxαxx2+c2y2),
where αx is the polarizability
αx=c(εx+1εx1+1c1+c)=c(1+c)(1εx)2(εx+c),
which has been normalized to make the last bracketed expression in (4.53) as simple as possible.

Similarly, when the applied field is in the y direction and x + icy and xicy are both large the potential given by (2.31) has the far field behavior

V(x,y)γ(εy+1)cy1εy+γ(1+c2)cy1c22γc2y1c2+γc2i(x+icy)γc2i(xicy)γcy(εy+11εy+1c1+c)γc2yx2+c2y2γcy(εy+11εy+1c1+c)(yyαyx2+c2y2),
where αy is the normalized polarizability
αy=c(εy+11εy+1c1+c)=c(1+c)(1εy)2(1+cεy).
We call (4.53) and (4.54) the dipole approximation for the far field. Note that in a hyperbolic medium it does not suffice for x2 + y2 to be large to ensure that both x + icy and xicy are large. One must also be sufficiently distant from the lines x = ±μy since along these lines either x + icy or xicy is close to zero when η is small. Thus for the dipole approximation for the far field to be valid one must be sufficiently far from the four characteristic lines (3.41): this makes sense as the electric field diverges to infinity along these lines, whereas the dipole field only diverges on the two lines x = ±μy as η → 0.

The expressions (4.54) and (4.56) for the polarizabilities could have been obtained more easily from the far field expressions for the potential outside an elliptical hole in an isotropic medium. When c is real and positive and before the stretching, the elliptical hole has axis lengths of 2 and 2c and in the (u,v) plane. With an applied field in the u-direction the far field in the isotropic medium with dielectric constant εx has potential

uπcu(1εx)2π(u2+v2)[εx+(1εx)c1+c],
where πc is the area of the ellipse and c/(1+ c) is the depolarization factor of the ellipse in the u-direction. By making the transformation x = u, y = v/c this potential gets mapped to
xxαxx2+c2y2,
where the polarizability αx is given by (4.54). It is similarly easy to derive (4.56) using the depolarization factor 1/(1 + c) of the ellipse in the v direction. When c = 1 and εy = εx (4.54) and (4.56) reduce to αx = αy = (1 − εx)/(1 + εx) which (within a proportionality factor) is the polarizability of a hole in an isotropic medium having dielectric constant εx.

5. The response of two interacting polarizable dipoles in a hyperbolic medium

Here we study the mathematics of the interaction of two ideal polarizable dipoles in a hyperbolic medium. We leave open the question as to whether these ideal polarizable dipoles have any physical significance. Nevertheless the searchlight effect discussed here should motivate future studies to see, say, whether a distant very small circular disk, if appropriately positioned, can substantially influence the response of a large circular disk.

By definition a polarizable dipole with rectangular symmetry located at the origin responds to a local field acting on it in the x direction so that the potential V(x,y) close to the origin has the expansion

V(x,y)x+a1αx/2x+icyαx/2xicy=x+a1xαxx2+c2y2,
and responds to an local field acting on it in the y direction so that the potential V(x,y) close to the origin has the expansion
V(x,y)y+a2+αy/(2ic)x+icyαy/(2ic)xicy=y+a2yαyx2+c2y2.
Here we call αx and αy the polarizabilities of the polarizable dipole, a1 and a2 are constants, and c = η with η being small. By taking linear combinations, the response to an arbitrarily oriented local field is such that the potential close to the origin has the expansion
V(x,y)γxx+γyy+axγxαx+yγyαyx2+c2y2.

With c = − + η and η > 0 small, the potential on the right hand side of (5.59) now has a local time averaged power dissipation near the characteristic line x +μy = 0 of

Im(εy)|Vy|2μ2|αx|2Im(εy)4|g+iηy|4ηεx|αx|22μ(g2+η2y2)2,
where g = x + μy. So when η is very small the dissipation integrated with respect to g, in the range −g0gg0, is approximately
g0g0Im(εy)|Vy|2dgεx|αx|22μy3η2dν(ν2+1)2,
where ν = g/(ηy). Thus this power dissipation integrated across the characteristic line, per unit length of the characteristic line, blows up as η → 0.

Now consider a uniform applied field in the x-direction acting on two polarizable dipoles, each with rectangular symmetry, one located at the origin and the other at the point (x0, y0). The total field V(x,y) is the sum of the uniform field plus the two dipolar fields:

V(x,y)=x+xβ1x+yβ1yx2+c2y2+(xx0)β2x+(yy0)β2y(xx0)2+c2(yy0)2.
Expanding this around the origin x = y = 0 gives
V(x,y)xβ1x+yβ1yx2+c2y2(x0β2x+y0β2y)x02+c2y02+x+xβ2x+yβ2yx02+c2y02(2xx0+2yy0)(x0β2x+y0β2y)(x02+c2y02)2,
which allows us to identify the local field acting on the dipole at the origin. If (α1x, α1y) are the polarizability coefficients of the dipole at the origin then from (5.61) we have
β1x=[1β2xx02+c2y02+2x0(x0β2x+y0β2y)(x02+c2y02)2]α1x,β1y=[β2yx02+c2y02+2c2y0(x0β2x+y0β2y)(x02+c2y02)2]α1y.
In a similar fashion, by rewriting (5.64) as
V(x,y)=x0+(xx0)+[x0+(xx0)]β1x+[y0+(yy0)]β1y[x0+(xx0)]2+c2[y0+(yy0)]2+(xx0)β2x+(yy0)β2y(xx0)2+c2(yy0)2,
and expanding this around the point (x0, y0) we obtain
V(x,y)(xx0)β2x+(yy0)β2y(xx0)2+c2(yy0)2+x0+(x0β1x+y0β1y)x02+c2y02+(xx0)+(xx0)β1x+(yy0)β1yx02+c2y02[2(xx0)x0+2(yy0)y0](x0β1x+y0β1y)(x02+c2y02)2.
So if (α2x, α2y) are the polarizability coefficients of the dipole at the point (x0, y0) then we have
β2x=[1β1xx02+c2y02+2x0(x0β1x+y0β1y)(x02+c2y02)2]α2x,β2y=[β1yx02+c2y02+2c2y0(x0β1x+y0β1y)(x02+c2y02)2]α2y.
Introducing
e=x02+c2y02x02μ2y022iμηy02,
in terms of which c2=(ex02)/y02, the equations (5.66) and (5.69) take the equivalent form
β1xα1x=1β2xe+2x0(x0β2x+y0β2y)e2,β1yα1y=β2ye+2(ex02)(x0β2x+y0β2y)y0e2,β2xα2x=1β1xe+2x0(x0β1x+y0β1y)e2,β2yα2y=β1ye+2(ex02)(x0β1x+y0β1y)y0e2.
These four equations have the solution
β[β1xβ1yβ2xβ2y]=A1[1010],
where A is the matrix
A=[1α1x01e2x02e22x0y0e201α1y2x0(ex02)e2y01e+2x02e21e2x02e22x0y0e21α2x02x0(ex02)e2y01e+2x02e201α2y],
which has determinant
det(A)=[4x02(ex02)(α1xα1y)(α2xα2y)+(e2α1xα2x)(e2α1yα2y)]e4α1xα1yα2xα2y,
that vanishes when x02 solves the quadratic
4x02(ex02)(α1xα1y)(α2xα2y)+(e2α1xα2x)(e2α1yα2y)=0.

We are interested in what happens to this solution when x0 and y0 are such that e is very small. Using Maple to compute the matrix inverse and taking the limit e → 0 we find that

β[2x02α1xα1y[2x02(α2yα2x)+α2yα2x]α1yα2yα1xα2x4x04(α1xα1y)(α2xα2y)2x03α1xα1y[2x02(α2yα2x)+α2yα2x]y0[α1yα2yα1xα2x4x04(α1xα1y)(α2xα2y)]2x02α2xα2y[2x02(α1yα1x)+α1xα1y]α1yα2yα1xα2x4x04(α1xα1y)(α2xα2y)2x03α2yα2x[2x02(α1yα1x)+α1xα1y]y0[α1yα2yα1xα2x4x04(α1xα1y)(α2xα2y)]].
Thus when α1xα1y and α2xα2y we see that in the limit e → 0 all components of β blow up to infinity when x0 is such that
x04=α1xα1yα2xα2y4(α1xα1y)(α2xα2y),
which is in agreement with (5.75) when one sets e = 0. Of course this equation generally will not have a solution for real x0 if any of the polarizabilities are complex.

Additionally let us suppose that the polarizabilities α2x and α2y are very small, and α2xα2y. Specifically let suppose that α2y = 2x, where k is a fixed constant not equal to 1. Then if the limit α2x → 0 is taken after the limit e → 0, (5.76) implies

β[α1xα1yα1xα1yα1xα1yx0(α1xα1y)y000].
By contrast if α2y = 2x, where k is a fixed constant, and we take the limit α2x → 0 directly in (5.72), keeping e fixed and non-zero, then we obtain
β[α1x000].
Thus even a polarizable dipole at (x0, y0) with very small polarizability can have a very large effect on the net dipole moments of the system if it is positioned close to one of the characteristic lines where e is small. Even though its polarizability is small the field exerted by this dipole on the dipole at the origin is still significant. We call this the searchlight effect since μ and thus the angle of the characteristic lines will depend on frequency, so by varying the frequency and observing the net dipole moments of the system one may hope to detect something about the relative location of the polarizable dipoles, even though one of the polarizable dipoles, by itself, is difficult to detect. The effect is illustrated in Figs. 2 and 3.

 figure: Fig. 2

Fig. 2 Plot of the absolute value of the dipole amplitude β1x near the line where e ≈ 0 with polarizabilities α1x = 2, and α1y = 1, α2x = 0.2, and α2y = 0.1 and parameter c = 0.01 − i. We use rotated coordinates ξ=(x0+y0)/2 and τ=(x0y0)/2. Note the long-range interaction.

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 figure: Fig. 3

Fig. 3 Same as Fig. 2 but with polarizabilities α1x = 2, and α1y = 1, α2x = 0.1, and α2y = 0.2 and parameter c = 0.01 − i.

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The case k = 1 when α2y = α2x is rather special, but very interesting. In this case, with e → 0 (5.76) simplifies to

β[2x022x03y02x02(α1xα1y2x02α1x+2x02α1y)α1xα1y2x03(α1xα1y2x02α1x+2x02α1y)y0α1yα1x],
and this result does not depend on the magnitude of α2x. Remarkably, note that the magnitudes of the components of β increase as x0 increases: recalling that when e = 0, y0 = ±x0/(ic) we see that β1x and β1y increase as x02, while β2x and β2y increase as x04 when α1xα1y and as x02 when α1x = α1y. Thus the interaction increases the further the polarizable dipoles are apart!

To shed more light on this one can, using Maple, directly compute the right hand side of (5.72) when α2y = α2x to obtain

β=[(e2+eα2x2x02α2x)α1xe2α1xα2x2α1yx0(ex02)α2x(e2α2xα1y)y0α2xf(e2α2xα1y)(e2α1xα2x)2x0(ex02)α2xgy0(e2α2xα1y)(e2α1xα2x)],
where
f=e3α1x2x02α1xe2eα1xα2xα1y+2x02α1xα2xα1ye4+4α1xα2xex024α1xα2xx04+α2xα1ye44x02α1yα2xe+4x04α1yα2x,g=α1xe2α1yα1xα2xα1xα2xe+α1yα2xe+2α1xα2xx022x02α1yα2x.

If the limit e → 0 is taken in this expression we recover (5.80). On the other hand it is evident from (5.81) that there are resonances when e2 equals α1xα2x or α1yα2x, and that the resulting expression for β depends crucially on the ratio of the magnitude of e2 to these two quantities. Also if η is non-zero the interaction decreases for sufficiently large separations of the polarizable dipoles. On the characteristic lines x0 = ± μy0 we have e2iμηy02. So for large x0 = ±μy0 (5.81) implies that, for example,

β1xx02α2xα1x2μ2η2y04=α2xα1x2η2y02,
which goes to zero as 1/y02 as y0. Figure 4 shows how, as the separation increases, the interaction along the characteristic line first increases, then decreases.

 figure: Fig. 4

Fig. 4 Plot of the absolute value of the dipole amplitude β1x near the line where e ≈ 0 with polarizabilities α1x = 2, and α1y = 1, α2x = α2y = 0.1 and parameter c = 0.01 − i. We use rotated coordinates ξ=(x0+y0)/2 and τ=(x0y0)/2. Note that the interaction along the line τ = 0 first becomes stronger as ξ increases, then weakens.

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Acknowledgments

Graeme Milton is thankful to Ben Eggleton, CUDOS and the University of Sydney for the provision of office space during his visit there and to the National Science Foundation for support through grant DMS-1211359. R.C. McPhedran acknowledges the support of the Australian Research Council through its Discovery Grant Scheme. The Centre for Ultrahighband-width Devices for Optical Systems (CUDOS) is an ARC Centre of Excellence (Project No. CE110001018).

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Figures (4)

Fig. 1
Fig. 1 Plot of the absolute value of the potential V(x,y) around the disk given by (2.26) with an applied field directed along the x-axis and with parameters γ′ = 1, εx = 3 and c = 0.01 − i. The potential has kinks at the four characteristic lines given by (3.41) which are also drawn. Near these lines the electric field is huge.
Fig. 2
Fig. 2 Plot of the absolute value of the dipole amplitude β1x near the line where e ≈ 0 with polarizabilities α1x = 2, and α1y = 1, α2x = 0.2, and α2y = 0.1 and parameter c = 0.01 − i. We use rotated coordinates ξ = ( x 0 + y 0 ) / 2 and τ = ( x 0 y 0 ) / 2. Note the long-range interaction.
Fig. 3
Fig. 3 Same as Fig. 2 but with polarizabilities α1x = 2, and α1y = 1, α2x = 0.1, and α2y = 0.2 and parameter c = 0.01 − i.
Fig. 4
Fig. 4 Plot of the absolute value of the dipole amplitude β1x near the line where e ≈ 0 with polarizabilities α1x = 2, and α1y = 1, α2x = α2y = 0.1 and parameter c = 0.01 − i. We use rotated coordinates ξ = ( x 0 + y 0 ) / 2 and τ = ( x 0 y 0 ) / 2. Note that the interaction along the line τ = 0 first becomes stronger as ξ increases, then weakens.

Equations (83)

Equations on this page are rendered with MathJax. Learn more.

V ˜ e ( z ) = 1 z z 0 ( 1 ε c 1 + ε c ) a 2 z 0 2 ( z a 2 / z 0 ) ,
ε V = 0 , ε = [ ε x 0 0 ε y ] .
2 V y 2 = μ 2 2 V x 2 ,
z + r 2 z = 2 w ,
u = ± ( r 0 + r 2 / r 0 ) / 2 , v = ± ( r 0 r 2 / r 0 ) / 2 .
z = w + w 2 r 2 , 1 z = w w 2 r 2 r 2 .
w 2 r 2 = ( w + r ) ( w r ) / ( w + r ) ,
γ ( z + r 2 / z ) / 2 = γ ( r 0 e i θ + r 2 e i θ / r 0 ) / 2 ,
γ ¯ 2 ( r 0 2 r 0 e i θ + r 2 r 0 e i θ r 0 2 ) = γ ¯ t ,
t = 1 2 ( r 0 2 z + r 2 z r 0 2 ) = w 2 ( r 2 r 0 2 + r 0 2 r 2 ) + w 2 r 2 2 ( r 2 r 0 2 r 0 2 r 2 ) .
x = u , y = v / c ,
x = ± ( r 0 + r 2 / r 0 ) / 2 , y = ± ( r 0 r 2 / r 0 ) / ( 2 c ) .
r 0 = 1 + c , r = 1 c 2 ,
( r 0 + r 2 / r 0 ) = 2 , ( r 0 r 2 / r 0 ) = 2 c .
ε = [ ε x 0 0 ε y ] ,
ε y = ε x / c 2 .
V ( x , y ) = Re ( β w + γ ¯ t ) for x 2 + y 2 1 , = δ x x + δ y y for x 2 + y 2 < 1 ,
t = ( 1 + c 2 ) ( x + i c y ) 1 c 2 + 2 c ( x + i c y ) 2 + c 2 1 c 2 1 .
Re [ ( β + γ ) w ] = δ x x + δ y y .
n x ε x x Re ( β w + γ ¯ t ) + n y ε y y Re ( β w + γ ¯ t ) = n x δ x + n y δ y ,
n x ε x x Re ( γ ¯ t ) + n y ε y y Re ( γ ¯ t ) = n x ε x x Re ( γ w ) + n y ε y y Re ( γ w ) ,
n x ε x x Re [ ( β γ ) w ] + n y ε y y Re [ ( β γ ) w ] = n x δ x + n y δ y .
β + γ = δ x , ε x ( β γ ) = δ x .
δ x = 2 γ ε x ε x 1 , β = γ ( ε x + 1 ) ε x 1 ,
V ( x , y ) = β x + γ Re ( t ) ,
V ( x , y ) = γ ( ε x + 1 ) x ε x 1 + γ ( 1 + c 2 ) x 1 c 2 + γ c [ ( x + i c y ) 2 + c 2 1 + ( x i c y ) 2 + c 2 1 ] c 2 1 ,
V ( x , y ) = δ x x = 2 γ ε x x ε x 1 .
c ( β + γ ) = δ y , ε y c ( β γ ) = δ y .
δ y = 2 c γ ε y 1 ε y , β = γ ( ε y + 1 ) ε y 1 ,
V ( x , y ) = β c y + γ Im ( t ) ,
V ( x , y ) = γ ( ε y + 1 ) c y 1 ε y + γ ( 1 + c 2 ) c y 1 c 2 + γ c [ ( x + i c y ) 2 + c 2 1 ( x i c y ) 2 + c 2 1 ] i ( c 2 1 ) ,
V ( x , y ) = δ y y = 2 c γ ε y y 1 ε y .
( x + i c y ) 2 + c 2 1 = ( x + i c y + 1 c 2 ) x + i c y 1 c 2 x + i c y + 1 c 2 ,
( x i c y ) 2 + c 2 1 = ( x i c y + 1 c 2 ) x i c y 1 c 2 x i c y + 1 c 2 ,
x + i c y 1 c 2 x + i c y + 1 c 2 = x + i c ¯ y 1 c 2 ¯ x i c ¯ y + 1 c 2 ¯ ,
y Re [ c ¯ 1 c 2 ] = x Im [ 1 c 2 ] .
( x , y ) = ± ( Re [ c ¯ 1 c 2 ] Re [ c ] , Im [ 1 c 2 ] Re [ c ] ) ,
( Re [ c ] ) 2 ( Re [ c ¯ 1 c 2 ] ) 2 ( Im [ 1 c 2 ] ) 2 > 0 .
ε y = ε x / ( i μ + η ) 2 ε x / μ 2 + 2 i ε x η / μ 3
( x + i c y ) 2 + c 2 1 = ( x + μ y + i η y + 1 c 2 ) ( x + μ y + i η y 1 c 2 ) , ( x i c y ) 2 + c 2 1 = ( x μ y i η y + 1 c 2 ) ( x μ y i η y 1 c 2 ) ,
x + μ y + 1 + μ 2 = 0 , x + μ y 1 + μ 2 = 0 , x μ y + 1 + μ 2 = 0 , x μ y 1 + μ 2 = 0 ,
( x , y ) = ( ± 1 / 1 + μ 2 , ± μ / 1 + μ 2 ) .
V ( x , y ) = H ( x , y ) + G ( x , y ) x + μ y + i η y + r ,
r = 1 c 2 1 + μ 2 + i μ η 1 + μ 2 , H ( x , y ) = γ ( ε x + 1 ) x ε x 1 + γ ( 1 + c 2 ) x 1 c 2 + γ c ( x i c y ) 2 r 2 c 2 1 , G ( x , y ) = γ c x + i c y r c 2 1 .
V y μ G 0 x + μ y + i η y + r μ G 0 h + i η s ,
G 0 = γ i μ 2 1 + μ 2 1 + μ 2 = γ μ 2 ( 1 + μ 2 ) 3 / 4
h = x + μ y + 1 + μ 2 , s = y + μ 1 + μ 2 .
Im ( ε y ) | V y | 2 | G 0 | 2 μ 2 Im ( ε y ) | h + i η s | 2 η ε x | G 0 | 2 μ h 2 + η 2 s 2 ,
0 h 0 d h h 2 + η 2 s 2 = ln ( h 0 + h 2 + η 2 s 2 ) ln ( η | s | ) ,
Im ( ε y ) | V y | 2 d h 4 ε x | G 0 | 2 η ln ( η | s | ) .
2 0 1 / η 4 ε x | G 0 | 2 η ln ( η | s | ) d s = 8 ε x | G 0 | 2 .
( x + i c y ) 2 + c 2 1 x + i c y + c 2 1 2 ( x + i c y ) , ( x i c y ) 2 + c 2 1 x i c y + c 2 1 2 ( x i c y ) ,
V ( x , y ) γ ( ε x + 1 ) x ε x 1 + γ ( 1 + c 2 ) x 1 c 2 2 γ c x 1 c 2 + γ c 2 ( x + i c y ) + γ c 2 ( x i c y ) γ x ( ε x + 1 ε x 1 + 1 c 1 + c ) + γ c x x 2 + c 2 y 2 γ ( ε x + 1 ε x 1 + 1 c 1 + c ) ( x x α x x 2 + c 2 y 2 ) ,
α x = c ( ε x + 1 ε x 1 + 1 c 1 + c ) = c ( 1 + c ) ( 1 ε x ) 2 ( ε x + c ) ,
V ( x , y ) γ ( ε y + 1 ) c y 1 ε y + γ ( 1 + c 2 ) c y 1 c 2 2 γ c 2 y 1 c 2 + γ c 2 i ( x + i c y ) γ c 2 i ( x i c y ) γ c y ( ε y + 1 1 ε y + 1 c 1 + c ) γ c 2 y x 2 + c 2 y 2 γ c y ( ε y + 1 1 ε y + 1 c 1 + c ) ( y y α y x 2 + c 2 y 2 ) ,
α y = c ( ε y + 1 1 ε y + 1 c 1 + c ) = c ( 1 + c ) ( 1 ε y ) 2 ( 1 + c ε y ) .
u π c u ( 1 ε x ) 2 π ( u 2 + v 2 ) [ ε x + ( 1 ε x ) c 1 + c ] ,
x x α x x 2 + c 2 y 2 ,
V ( x , y ) x + a 1 α x / 2 x + i c y α x / 2 x i c y = x + a 1 x α x x 2 + c 2 y 2 ,
V ( x , y ) y + a 2 + α y / ( 2 i c ) x + i c y α y / ( 2 i c ) x i c y = y + a 2 y α y x 2 + c 2 y 2 .
V ( x , y ) γ x x + γ y y + a x γ x α x + y γ y α y x 2 + c 2 y 2 .
Im ( ε y ) | V y | 2 μ 2 | α x | 2 Im ( ε y ) 4 | g + i η y | 4 η ε x | α x | 2 2 μ ( g 2 + η 2 y 2 ) 2 ,
g 0 g 0 Im ( ε y ) | V y | 2 d g ε x | α x | 2 2 μ y 3 η 2 d ν ( ν 2 + 1 ) 2 ,
V ( x , y ) = x + x β 1 x + y β 1 y x 2 + c 2 y 2 + ( x x 0 ) β 2 x + ( y y 0 ) β 2 y ( x x 0 ) 2 + c 2 ( y y 0 ) 2 .
V ( x , y ) x β 1 x + y β 1 y x 2 + c 2 y 2 ( x 0 β 2 x + y 0 β 2 y ) x 0 2 + c 2 y 0 2 + x + x β 2 x + y β 2 y x 0 2 + c 2 y 0 2 ( 2 x x 0 + 2 y y 0 ) ( x 0 β 2 x + y 0 β 2 y ) ( x 0 2 + c 2 y 0 2 ) 2 ,
β 1 x = [ 1 β 2 x x 0 2 + c 2 y 0 2 + 2 x 0 ( x 0 β 2 x + y 0 β 2 y ) ( x 0 2 + c 2 y 0 2 ) 2 ] α 1 x , β 1 y = [ β 2 y x 0 2 + c 2 y 0 2 + 2 c 2 y 0 ( x 0 β 2 x + y 0 β 2 y ) ( x 0 2 + c 2 y 0 2 ) 2 ] α 1 y .
V ( x , y ) = x 0 + ( x x 0 ) + [ x 0 + ( x x 0 ) ] β 1 x + [ y 0 + ( y y 0 ) ] β 1 y [ x 0 + ( x x 0 ) ] 2 + c 2 [ y 0 + ( y y 0 ) ] 2 + ( x x 0 ) β 2 x + ( y y 0 ) β 2 y ( x x 0 ) 2 + c 2 ( y y 0 ) 2 ,
V ( x , y ) ( x x 0 ) β 2 x + ( y y 0 ) β 2 y ( x x 0 ) 2 + c 2 ( y y 0 ) 2 + x 0 + ( x 0 β 1 x + y 0 β 1 y ) x 0 2 + c 2 y 0 2 + ( x x 0 ) + ( x x 0 ) β 1 x + ( y y 0 ) β 1 y x 0 2 + c 2 y 0 2 [ 2 ( x x 0 ) x 0 + 2 ( y y 0 ) y 0 ] ( x 0 β 1 x + y 0 β 1 y ) ( x 0 2 + c 2 y 0 2 ) 2 .
β 2 x = [ 1 β 1 x x 0 2 + c 2 y 0 2 + 2 x 0 ( x 0 β 1 x + y 0 β 1 y ) ( x 0 2 + c 2 y 0 2 ) 2 ] α 2 x , β 2 y = [ β 1 y x 0 2 + c 2 y 0 2 + 2 c 2 y 0 ( x 0 β 1 x + y 0 β 1 y ) ( x 0 2 + c 2 y 0 2 ) 2 ] α 2 y .
e = x 0 2 + c 2 y 0 2 x 0 2 μ 2 y 0 2 2 i μ η y 0 2 ,
β 1 x α 1 x = 1 β 2 x e + 2 x 0 ( x 0 β 2 x + y 0 β 2 y ) e 2 , β 1 y α 1 y = β 2 y e + 2 ( e x 0 2 ) ( x 0 β 2 x + y 0 β 2 y ) y 0 e 2 , β 2 x α 2 x = 1 β 1 x e + 2 x 0 ( x 0 β 1 x + y 0 β 1 y ) e 2 , β 2 y α 2 y = β 1 y e + 2 ( e x 0 2 ) ( x 0 β 1 x + y 0 β 1 y ) y 0 e 2 .
β [ β 1 x β 1 y β 2 x β 2 y ] = A 1 [ 1 0 1 0 ] ,
A = [ 1 α 1 x 0 1 e 2 x 0 2 e 2 2 x 0 y 0 e 2 0 1 α 1 y 2 x 0 ( e x 0 2 ) e 2 y 0 1 e + 2 x 0 2 e 2 1 e 2 x 0 2 e 2 2 x 0 y 0 e 2 1 α 2 x 0 2 x 0 ( e x 0 2 ) e 2 y 0 1 e + 2 x 0 2 e 2 0 1 α 2 y ] ,
det ( A ) = [ 4 x 0 2 ( e x 0 2 ) ( α 1 x α 1 y ) ( α 2 x α 2 y ) + ( e 2 α 1 x α 2 x ) ( e 2 α 1 y α 2 y ) ] e 4 α 1 x α 1 y α 2 x α 2 y ,
4 x 0 2 ( e x 0 2 ) ( α 1 x α 1 y ) ( α 2 x α 2 y ) + ( e 2 α 1 x α 2 x ) ( e 2 α 1 y α 2 y ) = 0 .
β [ 2 x 0 2 α 1 x α 1 y [ 2 x 0 2 ( α 2 y α 2 x ) + α 2 y α 2 x ] α 1 y α 2 y α 1 x α 2 x 4 x 0 4 ( α 1 x α 1 y ) ( α 2 x α 2 y ) 2 x 0 3 α 1 x α 1 y [ 2 x 0 2 ( α 2 y α 2 x ) + α 2 y α 2 x ] y 0 [ α 1 y α 2 y α 1 x α 2 x 4 x 0 4 ( α 1 x α 1 y ) ( α 2 x α 2 y ) ] 2 x 0 2 α 2 x α 2 y [ 2 x 0 2 ( α 1 y α 1 x ) + α 1 x α 1 y ] α 1 y α 2 y α 1 x α 2 x 4 x 0 4 ( α 1 x α 1 y ) ( α 2 x α 2 y ) 2 x 0 3 α 2 y α 2 x [ 2 x 0 2 ( α 1 y α 1 x ) + α 1 x α 1 y ] y 0 [ α 1 y α 2 y α 1 x α 2 x 4 x 0 4 ( α 1 x α 1 y ) ( α 2 x α 2 y ) ] ] .
x 0 4 = α 1 x α 1 y α 2 x α 2 y 4 ( α 1 x α 1 y ) ( α 2 x α 2 y ) ,
β [ α 1 x α 1 y α 1 x α 1 y α 1 x α 1 y x 0 ( α 1 x α 1 y ) y 0 0 0 ] .
β [ α 1 x 0 0 0 ] .
β [ 2 x 0 2 2 x 0 3 y 0 2 x 0 2 ( α 1 x α 1 y 2 x 0 2 α 1 x + 2 x 0 2 α 1 y ) α 1 x α 1 y 2 x 0 3 ( α 1 x α 1 y 2 x 0 2 α 1 x + 2 x 0 2 α 1 y ) y 0 α 1 y α 1 x ] ,
β = [ ( e 2 + e α 2 x 2 x 0 2 α 2 x ) α 1 x e 2 α 1 x α 2 x 2 α 1 y x 0 ( e x 0 2 ) α 2 x ( e 2 α 2 x α 1 y ) y 0 α 2 x f ( e 2 α 2 x α 1 y ) ( e 2 α 1 x α 2 x ) 2 x 0 ( e x 0 2 ) α 2 x g y 0 ( e 2 α 2 x α 1 y ) ( e 2 α 1 x α 2 x ) ] ,
f = e 3 α 1 x 2 x 0 2 α 1 x e 2 e α 1 x α 2 x α 1 y + 2 x 0 2 α 1 x α 2 x α 1 y e 4 + 4 α 1 x α 2 x e x 0 2 4 α 1 x α 2 x x 0 4 + α 2 x α 1 y e 4 4 x 0 2 α 1 y α 2 x e + 4 x 0 4 α 1 y α 2 x , g = α 1 x e 2 α 1 y α 1 x α 2 x α 1 x α 2 x e + α 1 y α 2 x e + 2 α 1 x α 2 x x 0 2 2 x 0 2 α 1 y α 2 x .
β 1 x x 0 2 α 2 x α 1 x 2 μ 2 η 2 y 0 4 = α 2 x α 1 x 2 η 2 y 0 2 ,
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