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Heat accumulation during pulsed laser materials processing: erratum

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Abstract

With this erratum we aim to correct a transcription error that occurred in our previous paper: In Eq. (3)a)-(3c), Eq. (5), and Eq. (6) the Greek characters were not converted correctly. The properly formatted formulae are listed below. All other contents, calculations and conclusions of the original paper remain unchanged.

© 2014 Optical Society of America

Corrected formula

In the formulae (3a)-(3c) in [1], the roman characters r (just the first letter in the denominator), p, and k must be replaced by the Greek characters ρ, π, and κ, respectively. The formulae correctly read:

1DT1DT0=ΔT1D=Q1Dρcp4πκter24κt            (r2=z2)
2DT2D-T0=ΔT2D=Q2Dρcp(4πκt)2e-r24κt         (r2=x2+y2)
3DT3D-T0=ΔT3D=Q3Dρcp(4πκt)3e-r24κt         (r2=x2+y2+z2)
where ΔTnD is the temperature increase with respect to the initial temperature T0, nD[1,2,3], ρ is the mass density of the solid or liquid material, cp its specific heat capacity, κ = λth /(ρ cp) the temperature conductivity, λth the heat conductivity, t is time, and x,y,z are the spatial coordinates.

The same corrections apply to Eq. (5)

nDimTnD-T0=ΔTnD=QnDρcp(4πκt)nDe-1trnD24κ
and Eq. (6)

ΔTnD(t,N)=QnDΘ(t-N-1fL)ρcp(4πκ(t-N-1fL))nDe-1(t-N-1fL)rnD24κ.

The Heaviside function Θ is equal to zero for arguments <0 and equal to one for arguments ≥0.

All other contents, calculations and conclusions of the original paper are correct and remain unchanged. The description of the variables was not changed and is kept in the text for easier reading of the formulae.

References and Links

1. R. Weber, T. Graf, P. Berger, V. Onuseit, M. Wiedenmann, C. Freitag, and A. Feuer, “Heat accumulation during pulsed laser materials processing,” Opt. Express 22(9), 11312–11324 (2014). [CrossRef]   [PubMed]  

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Equations (5)

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T 1 D T 0 = Δ T 1 D = Q 1 D ρ c p 4 π κ t e r 2 4 κ t                         ( r 2 = z 2 )
T 2 D - T 0 = Δ T 2 D = Q 2 D ρ c p ( 4 π κ t ) 2 e - r 2 4 κ t                   ( r 2 = x 2 + y 2 )
T 3 D - T 0 = Δ T 3 D = Q 3 D ρ c p ( 4 π κ t ) 3 e - r 2 4 κ t                   ( r 2 = x 2 + y 2 + z 2 )
T n D - T 0 = Δ T n D = Q n D ρ c p ( 4 π κ t ) n D e - 1 t r n D 2 4 κ
Δ T n D ( t , N ) = Q n D Θ ( t - N - 1 f L ) ρ c p ( 4 π κ ( t - N - 1 f L ) ) n D e - 1 ( t - N - 1 f L ) r n D 2 4 κ
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